Find ∫(sin x + 2)dx
- cos x + x2 + K
- cos x 2x + K
- -cos x + x2 + K
-
-cos x + 2x + K
The correct answer is: D
Explanation
∫(sin χ + 2)dχ = (∫sin χ + ∫2)dx
= -cos χ + 2χ + K
There is an explanation video available .