\(\begin{array}{c|c} Class Intervals & 0 – 2 & 3 – 5 & 6 – 8 & 9 – 11 & \\ \hline Frequency & 3 & 2 & 5 & 3 &\end{array}\)
Find the mode of the above distribution.
- 9
- 8
- 10
-
7
The correct answer is: D
Explanation
Mode = L1 + (\(\frac{D_1}{D_1 + D_2}\))CD1 = frequency of modal class - frequency of the class before it
D1 = 5 - 2 = 3
D2 = frequency of modal class - frequency of the class that offers it
D2 = 5 - 3 = 2
L1 = lower class boundary of the modal class
L1 = 5 - 5
C is the class width = 8 - 5.5 = 3
Mode = L1 + (\(\frac{D_1}{D_1 + D_2}\))C
= 5.5 + \(\frac{3}{2 + 3}\)C
= 5.5 + \(\frac{3}{5}\) x 3
= 5.5 + \(\frac{9}{5}\)
= 5.5 + 1.8
= 7.3 \(\approx\) = 7
There is an explanation video available .