\(\begin{array}{c|c} No & 0 & 1 & 2 & 3 & 4 & 5 \\ \hline Frequency & 1 & 4 & 3 & 8 & 2 & 5 \end{array}\). From the table above, find the median and range of the data respectively.
- (8,5)
-
(3, 5)
- (5 , 8)
- (5 , 3)
The correct answer is: B
Explanation
Median = \(\frac{\sum fx}{\sum f}\)\(\begin{array}{c|c}
No & 0 & 1 & 2 & 3 & 4 & 5 \\ F & 1 & 4 & 3 & 8 & 2 & 5 \\ fx & 0 & 4 & 6 & 24 & 8 & 25 \end{array}\)
\(\sum fx\) = 0 + 4 + 6 + 24 + 8 + 25 = 67
\(\sum f\) = 23
Median = \(\frac{\sum fx}{\sum f}\) = \(\frac{67}{23}\) = 2.913
= \(\approx\) 3
Range = 5 - 0 = 5
(3, 5)
There is an explanation video available .