If log3x2 = -8, what is x?
- \(\frac{1}{3}\)
- \(\frac{1}{9}\)
- \(\frac{1}{27}\)
-
\(\frac{1}{81}\)
The correct answer is: D
Explanation
log3x2 = -8x2 = 3-8
x = \(3^{-8 \times \frac{1}{2}}\)
x = 3-4
x = \(\frac{1}{3^4}\)
x = \(\frac{1}{81}\)
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