The probability that a student passes a physics test is \(\frac{2}{3}\). If he takes three physics tests, what is the probability that he passes two of the tests?
- \(\frac{2}{27}\)
- \(\frac{3}{27}\)
-
\(\frac{4}{27}\)
- \(\frac{5}{3}\)
The correct answer is: C
Explanation
Pass(P) = \(\frac{2}{3}\), Fail(F) = \(\frac{1}{3}\)T = P.P.F ==> \(\frac{2}{3} \times \frac{2}{3} \times \frac{1}{3}\) = \(\frac{4}{27}\)
There is an explanation video available .