A basket contains 9 apples, 8 bananas and 7 oranges. A fruit is picked from the basket, find the probability that it is neither an apple nor an orange.
- \(\frac{3}{8}\)
-
\(\frac{1}{3}\)
- \(\frac{7}{24}\)
- \(\frac{2}{3}\)
The correct answer is: B
Explanation
n(apples) = 9
n(bananas) = 8
n(oranges) = 7
n(\(\varepsilon\)) = 24
Hence Prob(not apple, nor orange) = Prob(banana) = \(\frac{8}{24}\) = \(\frac{1}{3}\)
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