If the angles of a quadrilateral are (3y + 10)°, (2y + 30)°, (y + 20)° and 4y°. Find the value of y.
- 66°
- 12°
-
30°
- 42°
The correct answer is: C
Explanation
Sum of angles in a quadrilateral = 360°
\(\therefore\) (3y + 10) + (2y + 30) + (y + 20) + 4y = 360
10y + 60 = 360 \(\implies\) 10y = 300
y = 30°
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