Find the length of a chord which subtends an angle of 90° at the centre of a circle whose radius is 8 cm.
- \(8\sqrt{3}\) cm
- 4 cm
- 8 cm
-
\(8\sqrt{2}\) cm
The correct answer is: D
Explanation
Length of chord = \(2r \sin (\frac{\theta}{2})\)
= \(2 \times 8 \times \sin (\frac{90}{2})\)
= \(16 \times \frac{\sqrt{2}}{2}\)
= \(8\sqrt{2} cm\)
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