Evaluate \(\int \sin 2x dx\)
- cos 2x + k
- \(\frac{1}{2}\)cos 2x + k
-
\(-\frac{1}{2}\)cos 2x + k
- -cos 2x + k
The correct answer is: C
Explanation
\(\int \sin 2x dx = \frac{1}{2} (-\cos 2x) + k\)\(- \frac{1}{2} \cos 2x + k\)
There is an explanation video available .