The mean of 2 – t, 4 + t, 3 – 2t, 2 + t and t – 1 is
- t
- -t
-
2
- -2
The correct answer is: C
Explanation
Mean x = \(\frac{\sum x}{n}\)
= [(2 - t) + (4 + t) + (3 - 2t) + (2 + t) + (t - 1)] \(\div\) 5
= [11 - 1 + 3t - 3t] \(\div\) 5
= 10 \(\div\) 5
= 2
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