In how many ways can a team of 3 girls be selected from 7 girls?
- \(\frac{7!}{3!}\)
- \(\frac{7!}{4!}\)
-
\(\frac{7!}{3!4!}\)
- \(\frac{7!}{2!5!}\)
The correct answer is: C
Explanation
A team of 2 girls can be selected from 7 girls in \(^7C_3\)\( = \frac{7!}{(7 - 3)! 3!}\)
\( = \frac{7!}{4! 3!} ways\)
There is an explanation video available .