\(\begin{array}{c|c}
Numbers & 1 & 2 & 3 & 4 & 5 & 6 \\
\hline
Frequency & 18 & 22 & 20 & 16 & 10 & 14
\end{array}\)
The table above represents the outcome of throwing a die 100 times. What is the probability of obtaining at least a 4?
- \(\frac{1}{5}\)
- \(\frac{1}{2}\)
-
\(\frac{2}{5}\)
- \(\frac{3}{4}\)
The correct answer is: C
Explanation
Let E demote the event of obtaining at least a 4Then n(E) = 16 + 10 + 14 = 40
Hence, prob (E) = \(\frac{n(E)}{n(S)}\)
\( = \frac{40}{100}\)
\( = \frac{2}{5}\)
There is an explanation video available .