In the figure above, KL//NM, LN bisects < KNM. If angles KLN is 54o and...

Explanation

In the diagram above, \(\alpha\) = 54^o(alternate angles; KL||MN) < KNM = 2\(\alpha\) (LN is bisector of < KNM) = 108^o

35^o + < KMN + 108^o = 180^o(sum of angles of \(\bigtriangleup\))

< KMN + 143^o = 180^o

< KMN = 180^o - 143^o

= 37^o

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