One bag contain 3 blue and 5 red balls, another bag contain 2 blue and 4 red balls respectively. One ball is drawn for each bag. What is the probability both balls are blue
- \( \frac{2}{15} \)
-
\( \frac{3}{24} \)
- \( \frac{3}{21} \)
- \( \frac{3}{28} \)
The correct answer is: B
Explanation
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