Determine the third term of a geometrical progression whose first and second term are 2 and 54 respectively
-
1458
- 1485
- 1345
- 1258
The correct answer is: A
Explanation
1st G.P. = a =2
2nd G.P. = ar\(^{2 −1}\) = 54
2(r) = 54
r = 54/2 = 27
r = 27
3rd term = ar\(^2\) = (2) (27)\(^2\)
2 × 27 × 27
= 1458
There is an explanation video available .