Evaluate \(\int\)(cos4x + sin3x)dx
- sin4x - cos3x + k
- sin4x + cos3x + k
-
\(\frac{1}{4}\)sin4x - \(\frac{1}{3}\)cos3x + k
- \(\frac{1}{4}\)sin4x + \(\frac{1}{3}\)cos3x + k
The correct answer is: C
Explanation
\(\int (\cos 4x + \sin 3x) \mathrm d x\)
= \(\frac{1}{4} \sin 4x - \frac{1}{3} \cos 3x + k\)
There is an explanation video available .