\(\begin{array}{c|c}
Marks & 2 & 3 & 4 \\
\hline
Frequency & 4 & 4 & y
\end{array}\)
The table above shows the frequency distribution of marks obtained by a group of students. If the total mark is 48, find the value of y.
- 6
- 8
-
7
- 5
The correct answer is: C
Explanation
(2 x 4) + (3 x 4) + (4 x y) = 488 + 12 + 4y = 48
4y = 48 - 20
\(\frac{4y}{4}\) = \(\frac{28}{4}\)
y = 7
There is an explanation video available .