A man covered a distance of 50 miles on his first trip, on a later trip he traveled 300 miles while going 3 times as fast. His new time compared with the old distance was?
- three times as much
- the same
-
twice as much
- half as much
The correct answer is: C
Explanation
Let the speed of the 1st trip be x miles/hrand the speed of the 2nd trip be 3x miles/hr
Speed = distance/time
∴ Time taken to cover a distance of 50 miles on the 1st trip
= \(\frac{50}{xhr}\)
time taken to cover a distance of 300 miles on the next trip
= \(\frac{300}{3xhr}\)
= \(\frac{100}{xhr}\)
∴the new time compared with the old time is twice as much
There is an explanation video available .