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Make S the subject of the relation p = s + \(\frac{sm^2}{nr}\)

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Mathematics JAMB 2017

Make S the subject of the relation
p = s + \(\frac{sm^2}{nr}\)

  • s = \(\frac{nrp}{nr + m^2}\) checkmark
  • s = nr + \(\frac{m^2}{mrp}\)
  • s = \(\frac{nrp}{mr}\) + m2
  • s = \(\frac{nrp}{nr}\) + m2

The correct answer is: A

Explanation

p = s + \(\frac{sm^2}{nr}\)

p = s + ( 1 + \(\frac{m^2}{nr}\))

p = s (1 + \(\frac{nr + m^2}{nr}\))

nr Γ— p = s (nr + m2)

s = \(\frac{nrp}{nr + m^2}\)

There is an explanation video available .

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