If y = 23\(_{five}\) + 101\(_{three}\) , find y, leaving your answer in base two

Explanation

y = 23\(_{five}\) + 101\(_{three}\)

23\(_{five}\) = \(2 \times 5^1 + 3 \times 5^0\)

= 13\(_{ten}\)

101\(_{three}\) = \(1 \times 3^2 + 0 \times 3^1 + 1 \times 3^0\)

= 10\(_{ten}\)

y\(_{ten}\) = 13\(_{ten}\) + 10\(_{ten}\)

= 23\(_{ten}\)

= 10111\(_{two}\)

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