If a fair coin is tossed 3 times, what is the probability of getting at least two heads?
- \(\frac{2}{3}\)
- \(\frac{4}{5}\)
- \(\frac{2}{5}\)
-
\(\frac{1}{2}\)
The correct answer is: D
Explanation
The outcomes are {HHH, HHT, HTT, HTH, THH, THT, TTH, TTT}
P(at least two heads) = \(\frac{4}{8}\)
= \(\frac{1}{2}\)
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