Express \((0.0439 \div 3.62)\) as a fraction.
- \(\frac{21}{100}\)
- \(\frac{21}{1000}\)
-
\(\frac{12}{1000}\)
- \(\frac{12}{100}\)
The correct answer is: C
Explanation
\((0.0439 \div 3.62)\)
= 0.01213
\(\approxeq\) 0.012
= \(\frac{12}{1000}\)
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