Integrate \(\int (4x^{-3} – 7x^2 + 5x – 6) \mathrm d x\).
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\(-2x^{-2} - \frac{7}{3}x^3 + \frac{5}{2} x^2 - 6x\)
- \(2x^2 + \frac{7}{3} x^3 - 5x + 6\)
- \(12x^2 + 14x - 5\)
- \(-12x^{-4} - 14x + 5\)
The correct answer is: A
Explanation
\(\int (4x^{-3} - 7x^2 + 5x - 6) \mathrm d x\)
= \(\frac{4x^{-3 + 1}}{-3 + 1} - \frac{7x^{2 + 1}}{2 + 1} + \frac{5x^{1 + 1}}{1 + 1} - 6x\)
= \(-2x^{-2} - \frac{7}{3} x^3 + \frac{5}{2} x^2 - 6x\)
There is an explanation video available .