If y = 8x\(^3\) – 3x\(^2\) + 7x – 1, find \(\frac{\mathrm d^2 y}{\mathrm d x^2}\).
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48x - 6
- 11x\(^2\) + 6x - 7
- 32x + 7
- 24x\(^2\) - 6x + 7
The correct answer is: A
Explanation
y = 8x\(^3\) - 3x\(^2\) + 7x - 1
\(\frac{\mathrm d^2 y}{\mathrm d x^2} = \frac{\mathrm d}{\mathrm d x} (\frac{\mathrm d y}{\mathrm d x})\)
= \(\frac{\mathrm d}{\mathrm d x} (24x^2 - 6x + 7)\)
\(\frac{\mathrm d^2 y}{\mathrm d x^2} = 48x - 6\)
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