If log\(_{10}\)2 = 0.3010 and log\(_{10}\)3 = 0.4771, eventually without using the logarithm tables, log\(_{10}\)4.5
- 0.3010
- 0.4771
-
0.6532
- 0.9542
The correct answer is: C
Explanation
log\(_{10}\)2 = 0.3010 and log\(_{10}\)3 = 04771
log\(_{10} 4.5 = log_{10}\) (\(\frac{3 \times 3}{2}\))
log\(_{10}\) 3 + log\(_{10}\) 3 - log\(_{10}\)2 = 0.4471 + 0.771 - 0.3010
= 0.6532
There is an explanation video available .