In this fiqure, PQ = PR = PS and SRT = 68\(^o\). Find QPS

Explanation

Since PQRS is quadrilateral

2y + 2x + QPS = 360\(^o\)

i.e. (y + x) + QPS = 360\(^o\) 

QPS = 360\(^o\) - 2 (y + x)

But x + y + 68\(^o\) = 180\(^o\)

There; x + y = 180\(^o\) - 68\(^o\) = 112\(^o\)

QPS = 360 - 2(112\(^o\))

= 360\(^o\) - 224 = 136\(^o\)

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