Find the probability that a number selected at random from 41 to 56 is a multiple of 9
-
\(\frac{1}{8}\)
- \(\frac{2}{15}\)
- \(\frac{3}{16}\)
- \(\frac{7}{8}\)
The correct answer is: A
Explanation
Given from 41 to 56
41, 42, 43, 44, 45, 46, 47, 48, 49, 50, 51, 52, 53, 54, 55, 56
The nos multiple of 9 are: 45, 54
P(multiple of 9) = \(\frac{2}{16}\)
= \(\frac{1}{8}\)
There is an explanation video available .