Simplify 2log \(\frac{2}{5}\) – log\(\frac{72}{125}\) + log 9
- 1 - 4 log3
- -1 + 2 log 3
- -1 + 5 log2
-
1 - 2log 2
The correct answer is: D
Explanation
2log \(\frac{2}{5}\) - log\(\frac{72}{125}\) + log 9
[\(\frac{2}{5}\))2 x 9] = log \(\frac{4}{25}\) x \(\frac{9}{1}\) x \(\frac{125}{72}\)
= log \(\frac{72}{125}\)
= log \(\frac{5}{2}\)
= log \(\frac{10}{4}\)
= log 10 - log 4
= log10 - log2\(^2\)
= 1 - 2 log2
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