X is due east point of y on a coast. Z is another point on the coast but 6.0km due south of Y. If the distance ZX is 12km, calculate the bearing of Z from X
-
240°
- 150°
- 60°
- 270°
The correct answer is: A
Explanation
Sinθ = \(\frac{6}{12}\)
Sinθ = \(\frac{1}{2}\)
θ = Sin\(^0.5\)
θ = 30°
Bearing of Z from X, (270 - 30)° = 240°
There is an explanation video available .