Evaluate Log\(_2\) 8√2

Explanation

where Log\(_2\) 8√2 → Log\(_2\) √128 

→ Log\(_2\) 128\(^\frac{1}{2}\)

= \(\frac{1}{2}\) * (Log\(_2\) 128) → \(\frac{1}{2}\) * (Log\(_2\) 2\(^7\))

=  7 * \(\frac{1}{2}\) * (Log\(_2\) 2)

where (Log\(_2\) 2) = 1 

→  7 * \(\frac{1}{2}\) * 1

= \(\frac{7}{2}\) or 3.5

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