If sec\(^2\)θ + tan\(^2\)θ = 3, then the angle θ is equal to?

Explanation

Given that sec\(^2\)θ + tan\(^2\)θ = 3

Where sec\(^2\)θ = 1  + tan\(^2\)θ

: 1 + tan\(^2\)θ + tan\(^2\)θ = 3

2tan\(^2\)θ = 3 - 1

2tan\(^2\)θ = 2

divide both sides by 2

tan\(^2\)θ = 1

tanθ =  √1

tanθ = 1

θ = tan\(^{-1}\) (1)

θ = 45º

There is an explanation video available .