The equivalent of (10110.011)\(_2\) in base 10 is?
The correct answer is: D
Explanation
Using the expansion method on (10110.011)\(_2\)
(1 * 2\(^4\)) + (0 * 2\(^3\)) + (1 * 2\(^2\)) + (1 * 2\(^1\)) (0 * 2\(^0\)) + (0 * 2\(^{-1}\)) + (1 * 2\(^{-2}\)) + (1 * 2\(^{-3}\))
(1*16) + 0 (1*4) + (1*2) + 0 + 0 + (1*\(\frac{1}{4}\)) + (1*\(\frac{1}{8}\))
16 + 4 + 2 + (0.25 + 0.125)
22 + 0.375
(10110.011)\(_2\) = 22.375\(_{10}\)
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