Given that S = \(3t^{2}\) + 5t – 10 is displacement of a particle in metres, calculate it initial velocity.
- 10m/s
- 2m/s
-
5m/s
- 6m/s
The correct answer is: C
Explanation
The initial velocity (v) is obtained by differentiating the displacement (S) with respect to time, which gives:
v = \(\frac{dS}{dt}\) = \(\frac{d}{dt}\)(\(3t^2\) + 5t - 10) = 6t + 5
The initial velocity is the velocity of the particle at time t = 0. Substituting t = 0 into the velocity equation:
v(0) = 6(0) + 5 = 5
Therefore, the initial velocity of the particle is 5 m/s.
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