Evaluate the following limit: \(lim_{x\to2} \frac {x^2 + 4x – 12}{x^2 – 2x}\)

Explanation

\(lim_{x\to2} \frac {x^2 + 4x - 12}{x^2 - 2x}\) = \(lim_{x\to2} \frac {(x - 2)(x + 6)}{x(x - 2)}\)

\(lim_{x\to2} \frac {x + 6}{x}\)

\(\frac {2 + 6}{2} = \frac {8}{2}\) = 4

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