Find the perimeter of a triangle whose vertices pass through ( 3, 2), (4, 5) and (6, 2) in surd form.
- 3 + \(\sqrt{12} + \sqrt{13}\)
- 3 - \(\sqrt{10} + \sqrt{13}\)
-
3 + \(\sqrt{10} + \sqrt{13}\)
- 3 - \(\sqrt{12} + \sqrt{13}\)
The correct answer is: C
Explanation
From the diagram above, Calculate the distance between any two vertices as follows.
PQ = \(\sqrt{(6 - 3)^2 + (2-2)^2}\) = \(\sqrt{9}\) = 3
QR = \(\sqrt{(6 - 4)^2 + (2-5)^2}\) = \(\sqrt{13}\)
PR = \(\sqrt{(4 - 3)^2 + (5 - 1)^2}\) = \(\sqrt{10}\)
\(\therefore\), perimeter = 3 + \(\sqrt{13}\) + \(\sqrt{10}\)
There is an explanation video available .