If B varies inversely as c\(^{\frac{1}{3}}\) and C = 27 when B = 2, find the value of the constant of proportionality K.
- 3
-
6
- 9
- 12
The correct answer is: B
Explanation
B = \(\frac{K}{C^{\frac{1}{3}}}\)
2 = \(\frac{K}{27^{\frac{1}{3}}}\)
K = 2 x 3 = 6
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