Make q the subject of the relation t = \(\sqrt{(\frac{pq}{r} – r^2q)}\)
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q = \(\frac{rt^2}{p - r^3}\)
- q = \(\frac{p - r^3}{rt^2}\)
- q = \(\frac{t^2}{p - r^3}\)
- q = \(\frac{rt}{p - r^3}\)
The correct answer is: A
Explanation
t = \(\sqrt{(\frac{pq}{r} - r^2q)}\)
Take the square of both sides
t\(^2\) = \(\frac{pq}{r}\) - r\(^2\)q
t\(^2\) = \(\frac{pq - r^3q}{r}\)
cross multiply
rt\(^2\) = pq - r\(^3\)q = q(p - r\(^3\))
q = \(\frac{rt^2}{p - r^3}\)
There is an explanation video available .