The angle of elevation of the top T of a pole from a point X on the horizontal ground is 32°, if X is 68 m away from the foot F of the pole, calculate the height FT of the pole, correct to one decimal place.
- 128.3m
- 108.8m
- 80.2m
- 57.7m
-
42.5m
The correct answer is: E
Explanation
to calculate for the high of the pole, we use sohcahtoa
Let the height of the pole be x.
Tan32º = \(\frac{opp}{adj}\)
Tan32º = \(\frac{x}{68}\)
x = Tan32º x 68 = 42.5m ( to 1 d.p)