Divide the LCM of 15abc and 20a\(^2\)bc by their HCF

Explanation

LCM of 15abc and 20a\(^2\)bc = 60a\(^2\)bc

Factors of 15abc = 1, 3, 5,15, a, b, c     

and of  20a\(^2\)bc = 1, 2, 4, 5, 10, 20, a, b, c

HCF of 15abc and 20a\(^2\)bc = 5abc

→ LCM ÷ HCF = 60a\(^2\)bc ÷ 5abc

= 12a