Given that x2 + y2 + k = 60 and x = \(\sqrt{10}\) when y = 4, find the value of k.
- 56
-
34
- 32
- -34
- -56
The correct answer is: B
Explanation
x\(^2\) + y\(^2\) + k = 60
(√10)\(^2\) + (4)\(^2\) + k = 60
k + 10 + 16 = 60
k = 60 - 26
k = 34