What is the probability of having an odd number in a single toss of a fair die?
- 1/6
- 1/3
-
1/2
- 2/3
- 5/6
The correct answer is: C
Explanation
n(S) = 6(odd) = {1, 3, 5}n(odd) = 3
pr(odd) = \(\frac{n(odd)}{n(S)}\) 3/6 =1/2