In the diagram O is the center of the circle, if ∠QRS = 62o, find the value of ∠SQR.
- 14o
-
28o
- 31o
- 45o
- 90o
The correct answer is: B
Explanation
< QSR = 90° (angle in a semi-circle)
\(\therefore\) < SQR = 180° - (90° + 62°)
= 28°