The table shows the weights, to the nearest kilogram, of twelve students in a Further Mathematics class
| Weight in kg | 55 | 57 | 59 | 61 | 63 |
| No of students | 2 | 1 | 2 | 4 | 3 |
(a) Draw a bar chart to illustrate the above information;
(b) What is (i) the mode; (ii) the median of the distribution?
(c) Calculate the mean weight correct to the nearest kilogram.
Explanation
(a) 
(b)(i) The mode is 61kg.
(ii) From the total number of students = 12, then the median is the average of the 6th and 7th weight.
From the table, the median = 61kg.
(c) Mean weight = \(\frac{\sum fx}{\sum f} = \frac{55 \times 2 + 57 \times 1 + 59 \times 2 + 61 \times 4 + 63 \times 3}{12}\)
= \(\frac{110 + 57 + 118 + 244 + 189}{12} = \frac{718}{12} = 59.833kg\)
\(\approxeq 60kg\)