Find the value of m which makes x\(^2\) + 8 + m a perfect square
The correct answer is: E
Explanation
x\(^2\) + 8 + m
To make it a perfect square, we add \((\frac{b}{2})^2\)
= \((\frac{8}{2})^2\)
= 16
Find the value of m which makes x\(^2\) + 8 + m a perfect square
x\(^2\) + 8 + m
To make it a perfect square, we add \((\frac{b}{2})^2\)
= \((\frac{8}{2})^2\)
= 16