The first term a of an A.P is equal to twice the
common difference d. Find, in terms of d, the 5th
term of the A.P.
- 4d
- 5d
-
6d
- a + 5d
- 2a + 4d
The correct answer is: C
Explanation
Tn = a + (n - 1)d; AP; a = 2d; Tn = 2d + (n - 1)dT5 = 2d + (5 - 1)d = 2d + 4d = 6d