In the diagram above, ATR is a tangent at the point T to the circle center O, if ∠TOB = 145°, find ∠TAO
- 20o
- 35o
- 45o
-
55o
- 65o
The correct answer is: D
Explanation
From the figure, < ATO = 90°
< AOT = 180° - 145° = 35°
\(\therefore\) < TAO = 180° - (90° + 35°)
= 55° (sum of angle in a triangle)