The nth term of a sequence is given by 3.2(^{n-2}). Write down the first three...

The nth term of a sequence is given by 3.2\(^{n-2}\). Write down the first three terms of the sequence.

The correct answer is: B

\(T_n = 3. 2^{n - 2} \\

T_{1} = 3. 2^{1 - 2} = 3. 2^{-1} \\

T_1 = \frac{3}{2} \)

\(T_2 = 3. 2^{2 - 2} \\

T_2 = 3. 2^0 = 3\)

\(T_3 = 3. 2^{3 - 2} = 3. 2^1 \\

T_3 = 6\)

The first 3 terms of the sequence are \(\frac{3}{2}\), 3 and 6.