The nth term of a sequence is given by 3.2\(^{n-2}\). Write down the first three terms of the sequence.
- 2/3, 0, 6
-
3/2, 3, 6,
- 2/3, 3, 8/3
- 2/3, 3/4, 6
- 2/3, 3, 1/3
The correct answer is: B
Explanation
\(T_n = 3. 2^{n - 2} \\
T_{1} = 3. 2^{1 - 2} = 3. 2^{-1} \\
T_1 = \frac{3}{2} \)
\(T_2 = 3. 2^{2 - 2} \\
T_2 = 3. 2^0 = 3\)
\(T_3 = 3. 2^{3 - 2} = 3. 2^1 \\
T_3 = 6\)
The first 3 terms of the sequence are \(\frac{3}{2}\), 3 and 6.