Evaluate \(\log_{10} 25 + \log_{10} 32 – \log_{10} 8\)
The correct answer is: B
Explanation
\(\log_{10} 25 + \log_{10} 32 - \log_{10} 8\)
= \(\log_{10} (\frac{25 \times 32}{8})\)
= \(\log_{10} 100 \)
= 2
Evaluate \(\log_{10} 25 + \log_{10} 32 – \log_{10} 8\)
\(\log_{10} 25 + \log_{10} 32 - \log_{10} 8\)
= \(\log_{10} (\frac{25 \times 32}{8})\)
= \(\log_{10} 100 \)
= 2