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Evaluate \(\log_{10} 25 + \log_{10} 32 – \log_{10} 8\)

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Mathematics WAEC 1992

Evaluate \(\log_{10} 25 + \log_{10} 32 – \log_{10} 8\)

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The correct answer is: B

Explanation

\(\log_{10} 25 + \log_{10} 32 - \log_{10} 8\)

= \(\log_{10} (\frac{25 \times 32}{8})\)

= \(\log_{10} 100 \)

= 2

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