In the diagram above, O is the center of the circle PQRS and ∠QPS = 36°. Find ∠QOS
- 36o
-
72o
- 108o
- 144o
- 288o
The correct answer is: B
Explanation
< QOS = 2 < QPS (angle subtended at the centre)
\(\therefore\) < QOS = 2 x 36° = 72°