A sector of a circle of radius 9cm subtends angle 120° at the centre of the circle. Find the area of the sector to the nearest cm\(^2\) [Take π = 22/7]
- 75cm2
- 84cm2
-
85cm2
- 86cm2
- 95cm2
The correct answer is: C
Explanation
Area of a sector = θ/360 x πr\(^2\)
= 120/360 x 22/7 x 81/1
= 84.86 cm\(^2\)
\(\approxeq\) 85cm\(^2\) (to the nearest cm)